Flexsim常用数学函数简介

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ceil
(num num)

天花板，向上取整。

Example

double myval =ceil(2.3); // Sets myval to 3.
double myval = ceil(3.8); // Sets myval to 4.
double myval = ceil(-2.3); // Sets myval to -2.
double myval = ceil(-3.8); // Sets myval to -3.
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floor
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地板，向下取整。

Example

double myval = floor(2.3); // Sets myvalto 2.
" F; x+ F; I7 a+ n; vdouble myval = floor(3.8); // Sets myval to 3.
( y1 K1 n3 _4 R% D2 Kdouble myval = floor(-2.3); // Sets myval to -3.
+ i7 f- Y7 g$ d  M( {- ydouble myval = floor(-3.8); // Sets myval to -4.

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round
3 i8 i( f% o) z) M(num value[, num precision])

根据指定的小数位数进行四舍五入。

Example

int mynum1 = round(3.6269);
/ g3 w% [( v% ^& F3 S) I6 Eint mynum2 = round(3.6269,2);

: W  ?& a. i9 Pmynum1 will be 4, and mynum2 will be 3.63.

trunc
(num value)

去除小数部分取整。Truncation

Example

trunc(2.478), returns 2

trunc(2.95), returns 2
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frac
(num value)

取小数点之后的部分。

Example

frac(3.124) returns 0.124
frac(-16.12) returns -0.12
frac(12) returns 0.0

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sign
(num value)

决断正负零，正数返回1，负数返回-1，0返回0。

Example

sign(-1)

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fabs
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绝对值。

Example

if(fabs(x1 - x2) > 5)

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factorial
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阶乘。

Example

factorial(5)

# b& i& x. G3 yThis calculates the factorial of 5, which is 1*2*3*4*5 = 120

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fmod
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取余。

Description

Remainder of value1/value2. fmod returnsthe floating-point remainder of value1 / value2. If the value of b is 0.0, fmodreturns a quiet NaN.
. j" `$ W% T$ g- jThis command is great for getting a repeating set ofnumbers because no matter what value1 is, so long as value2 is unchanged, fmodwill return a set of numbers that keeps repeating itself.

Example

fmod(10,3) This returns the remainder of 10/3, which is 1.0
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if(fmod(current.stats.output,10) == 0)
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7 @( S6 W4 T+ X9 ~" n9 z  YIf this condition was in the OnExit of an object in the model, it would be truewith every 10th flowitem that exits, starting with the 10th flowitem.

pow
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乘方。

Example

double myval = pow(2,3); Sets myval to 8.

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sqr
(num value)

平方Square of value.

Example

sqr(2)
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sqrt
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平方根Square root of value

Example

sqrt(10) This expression will return 3.16

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比如，我们要计算托盘上有多少层货物。
% \' V% z: d8 U& w4 U; A% K默认情况下，pallet上面每层可以放置4个box。也就是说，1,2,3,4个box都算1层，5,6,7,8个box都算是2层。
( s& u0 h; t! {4 B此时可以用ceil函数向上取整，ceil(content(pallet)/4)即可得到正确的层数。

这个真的很有用~谢谢加老师、

Mark~谢谢加老师的分享

受教了