Flexsim常用数学函数简介

ceil
(num num)

天花板，向上取整。

Example

double myval =ceil(2.3); // Sets myval to 3.
double myval = ceil(3.8); // Sets myval to 4.
double myval = ceil(-2.3); // Sets myval to -2.
double myval = ceil(-3.8); // Sets myval to -3.
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floor
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地板，向下取整。

Example

double myval = floor(2.3); // Sets myvalto 2.
double myval = floor(3.8); // Sets myval to 3.
double myval = floor(-2.3); // Sets myval to -3.
double myval = floor(-3.8); // Sets myval to -4.
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round
4 ^  J$ k, \9 E% n; v$ z: q' S(num value[, num precision])

根据指定的小数位数进行四舍五入。

Example

int mynum1 = round(3.6269);
9 U0 M$ ?% R) Q! X6 [5 C, ]int mynum2 = round(3.6269,2);
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mynum1 will be 4, and mynum2 will be 3.63.

trunc
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去除小数部分取整。Truncation

Example

trunc(2.478), returns 2
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3 [' {% n8 ?' Q3 T' L4 X* dtrunc(2.95), returns 2

frac
(num value)

取小数点之后的部分。

Example

frac(3.124) returns 0.124
frac(-16.12) returns -0.12
frac(12) returns 0.0

sign
(num value)

决断正负零，正数返回1，负数返回-1，0返回0。

Example

sign(-1)
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fabs
(num value)

绝对值。

Example

if(fabs(x1 - x2) > 5)

factorial
(num value)

阶乘。

Example

factorial(5)

This calculates the factorial of 5, which is 1*2*3*4*5 = 120
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fmod
3 z/ j; g, N) s/ d; k* N" x2 x6 P9 P(num value1, numvalue2)

取余。

Description

Remainder of value1/value2. fmod returnsthe floating-point remainder of value1 / value2. If the value of b is 0.0, fmodreturns a quiet NaN.
This command is great for getting a repeating set ofnumbers because no matter what value1 is, so long as value2 is unchanged, fmodwill return a set of numbers that keeps repeating itself.

Example

fmod(10,3) This returns the remainder of 10/3, which is 1.0
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If this condition was in the OnExit of an object in the model, it would be truewith every 10th flowitem that exits, starting with the 10th flowitem.

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pow
8 E2 Y2 ]# v8 d' r2 ^3 v(num num1, numnum2)

乘方。

Example

double myval = pow(2,3); Sets myval to 8.

sqr
(num value)

平方Square of value.

Example

sqr(2)
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sqrt
(num value)

平方根Square root of value

Example

sqrt(10) This expression will return 3.16

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比如，我们要计算托盘上有多少层货物。
3 r# h+ O' U% r/ u1 u, k默认情况下，pallet上面每层可以放置4个box。也就是说，1,2,3,4个box都算1层，5,6,7,8个box都算是2层。
此时可以用ceil函数向上取整，ceil(content(pallet)/4)即可得到正确的层数。

这个真的很有用~谢谢加老师、

Mark~谢谢加老师的分享

受教了