请问一下。1 + GAMM(2.96, 2.07) 如何化作(location,scale,shape,stream)形式???~~~+ X1 ]6 f' A( i/ r* S/ _
' N( ?5 Z; g/ T. [. d8 g/ a是用arena做的函数拟合$ o. @+ L( L, d* x `3 B0 n
6 X% T' }1 _. E: {+ o1 t8 @+ m Distribution Summary# e/ v/ O- `7 U+ Y" E7 c. _8 s
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Distribution: Gamma - _, V: @( c9 R- E" x- z$ I& M4 c
Expression: 1 + GAMM(2.96, 2.07)
% v; k9 S8 A2 K1 Q4 nSquare Error: 0.030433* D5 t8 J1 N1 h, {) E
3 F! ]: z, G( m& O1 Q+ N& M V8 LChi Square Test; \# S/ k/ ], Y: E
Number of intervals = 37 \: b1 s4 U K* h4 ]; l8 L% }: g6 Y
Degrees of freedom = 0) T# u0 E8 @: P
Test Statistic = 1.948 [4 r/ G4 H5 v# T9 R; \
Corresponding p-value < 0.005
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! d7 r5 E" j. |0 f/ u) MKolmogorov-Smirnov Test
$ U/ ]1 r U- p# a Test Statistic = 0.104
# F2 x0 ]2 ?& Q Corresponding p-value > 0.15( O8 h' A; }6 x2 p2 K& p' ]8 z
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Data Summary
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3 H9 ^- o) S5 y$ lNumber of Data Points = 25! a+ y+ c6 l7 s$ y& M$ p# b3 w
Min Data Value = 1.3% W( |2 b# [! k9 \
Max Data Value = 19
( v" {; }" ~9 qSample Mean = 7.13; I9 P% N! r7 s2 @4 e
Sample Std Dev = 4.17+ c3 n& E! ~* Z O. X l
6 x' ?' i# Z! R- s% T6 z Histogram Summary
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& a. ]" n& t; k' h& Y _ j3 J; NHistogram Range = 1 to 199 \2 I" |! I% Z% m# D
Number of Intervals = 5 |