请问一下。1 + GAMM(2.96, 2.07) 如何化作(location,scale,shape,stream)形式???~~~" p! i. g5 Z* i- e( u. U h2 H
0 S4 S( f; X( _/ V" v* ^: B是用arena做的函数拟合
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Distribution Summary. n: g. Z0 t. C( `$ ^! x& \
4 W4 a4 \& C3 ]Distribution: Gamma ) | x2 d3 L& ? X4 m
Expression: 1 + GAMM(2.96, 2.07)* [5 s2 z2 X! G
Square Error: 0.030433' g4 w! |: }# s# t
) @- P9 P8 r3 M1 XChi Square Test
0 H& f0 Z8 @4 m5 s Number of intervals = 3
0 L& [' m$ G: m! Z4 j6 [ Degrees of freedom = 0; K* N7 d4 D0 z
Test Statistic = 1.94
2 C$ ?! h& B- ~) M: x! Q- S Corresponding p-value < 0.005; O$ p3 J7 Y& ]* f0 \5 q: M# T( a- s
! P4 v& G& s: u+ BKolmogorov-Smirnov Test
7 f0 o" X7 q4 ~' j" B [+ q Test Statistic = 0.104
2 a2 l: q1 D% [& r1 r: N( Y Corresponding p-value > 0.15
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Data Summary8 E1 Q6 |# i5 |" h
) }& A' O Q& _0 ANumber of Data Points = 25
2 {; a# z9 f! x7 S; ?$ o3 F. j9 xMin Data Value = 1.31 S+ P3 H/ q6 s5 m' {6 B1 C
Max Data Value = 198 } N2 s. O! I
Sample Mean = 7.13" V% F! _9 w" @
Sample Std Dev = 4.17( a5 E: m7 y2 ?1 [3 Z) |) X
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Histogram Summary' L1 b' W3 d0 N
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Histogram Range = 1 to 198 k8 \& M( d; w/ i9 r/ R! X5 T7 P5 v
Number of Intervals = 5 |