请问一下。1 + GAMM(2.96, 2.07) 如何化作(location,scale,shape,stream)形式???~~~3 F- a% y2 O: t( ~
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是用arena做的函数拟合. j+ \ R8 s" ^
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Distribution Summary
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Distribution: Gamma ; Y( K0 e3 |) u, b
Expression: 1 + GAMM(2.96, 2.07)
& |+ \4 y! U" @& K7 OSquare Error: 0.030433
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Chi Square Test
# N4 ]5 S. H, i7 I3 U2 k) }! _ Number of intervals = 3
% C& ^% Z- H e: x Degrees of freedom = 0( K! e3 z+ t( x6 b/ r) b
Test Statistic = 1.941 K( v( b9 y2 \6 x @
Corresponding p-value < 0.005) D& G Q0 R) p! ~
/ j6 ?, D0 z3 X6 q( ?Kolmogorov-Smirnov Test
/ R O8 X, T7 Z2 _, I8 x, j Test Statistic = 0.1043 z7 |8 c' Q- b/ X d* x1 A& e; Z
Corresponding p-value > 0.156 s' H: K* `7 _9 j* w( L/ n K
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Data Summary
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- q& \ x+ ?- s- V5 ^! zNumber of Data Points = 25
' l, b6 A% B, [: j3 u, M0 FMin Data Value = 1.3
. I" b" V+ T+ r9 C( l. eMax Data Value = 198 L$ f$ H0 S, k$ O# \7 o* \
Sample Mean = 7.13% L' F& c5 O0 h- p. U9 e4 x
Sample Std Dev = 4.17
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/ s5 y( |% Q$ v: o, _2 } Histogram Summary
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4 }0 x( w, {. ^! X* @' N# [2 zHistogram Range = 1 to 19
* U) h$ K K# s( _1 l, R3 h) SNumber of Intervals = 5 |