请问一下。1 + GAMM(2.96, 2.07) 如何化作(location,scale,shape,stream)形式???~~~3 s0 ~2 {/ J# U1 Q' E
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是用arena做的函数拟合0 v, O! Q: c- r/ t. X$ B
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Distribution Summary6 S1 Q2 X% W+ w; L. _0 V2 f* P) q
8 T: v/ \( h$ z% `Distribution: Gamma
! ^4 g I( F$ ^- o& S/ M6 k2 wExpression: 1 + GAMM(2.96, 2.07)
( o& f$ R/ Y' l& uSquare Error: 0.0304333 X W4 i; O+ u# m6 g1 l4 q
# \/ l8 z+ c4 X+ ]6 qChi Square Test. ?7 Q2 d3 \: D# B2 D
Number of intervals = 3
; M: @3 t; I( z3 M( z' B Degrees of freedom = 0 w3 v9 ~/ }$ A3 m4 q& ?# J
Test Statistic = 1.94
; O, n$ T; C8 H Corresponding p-value < 0.005/ g+ z/ W# b6 X6 {3 O3 U
: Z& n/ _" B% r- c4 S& y1 p& dKolmogorov-Smirnov Test3 ]- e ~3 N F
Test Statistic = 0.104
k7 P5 y' G! v. H; I3 n Corresponding p-value > 0.15& V$ |, N- b$ D
! r% N7 t! q4 [ Data Summary
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) w" X( F' o" X& O4 A7 uNumber of Data Points = 25
( i: a' D. J m% d/ F/ I6 JMin Data Value = 1.3/ N7 |( x( [+ ^( K
Max Data Value = 19
* _& s+ G8 H# N; }3 dSample Mean = 7.13
! @5 N; l4 \0 |, w! _" A+ E/ K% n8 f# TSample Std Dev = 4.175 X5 H. w8 \6 J* p% |+ n2 d
0 ^4 H R- f" p, M! B1 n Histogram Summary; a, ? Q, Y2 y9 a4 e# t' Z
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Histogram Range = 1 to 19) F! D+ w, W( a! o& m
Number of Intervals = 5 |