请问一下。1 + GAMM(2.96, 2.07) 如何化作(location,scale,shape,stream)形式???~~~! P' j9 s* O2 I! Z( t
% \$ _* z0 g; I是用arena做的函数拟合
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Distribution Summary
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' }1 j2 X2 t; T O3 jDistribution: Gamma + S- F2 Q# W: R4 b8 m7 E
Expression: 1 + GAMM(2.96, 2.07)& u* v, e2 A3 j) H3 G
Square Error: 0.030433/ }* u& ^6 d5 y& o
- Z$ R3 r% I5 f, S' bChi Square Test, f& s% g4 u& Y0 K! [
Number of intervals = 3
( p' D- M/ g' `% T, G6 O Degrees of freedom = 0: j1 S; A0 x- i9 \' ]. E! K
Test Statistic = 1.94
/ R0 m2 m( m) G( Z Corresponding p-value < 0.005
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+ ]4 U E" v. v8 aKolmogorov-Smirnov Test
3 L0 D+ `8 H# d+ q Test Statistic = 0.104' h- F4 q0 R4 b+ K7 ~3 J! D# |
Corresponding p-value > 0.15' B6 D* l1 `6 } i
0 q& Y5 p8 ~ ^1 F' h) \ Data Summary% D5 j/ S2 j9 e3 H, p- z
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Number of Data Points = 25
; w i I- c+ E8 sMin Data Value = 1.3
' z+ _/ r2 v! V5 \Max Data Value = 19
+ i# S* t5 P+ w) N, Y. P! gSample Mean = 7.13 W( V; z7 {# F' e/ X+ ?
Sample Std Dev = 4.17
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8 ?( x. L& q% R7 ` Histogram Summary/ n6 y: @' G8 n% E8 A6 b
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Histogram Range = 1 to 19+ Z$ e8 {5 F: c) A! O. y, t4 n
Number of Intervals = 5 |