Flexsim常用数学函数简介

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ceil
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天花板，向上取整。

Example

double myval =ceil(2.3); // Sets myval to 3.
double myval = ceil(3.8); // Sets myval to 4.
double myval = ceil(-2.3); // Sets myval to -2.
double myval = ceil(-3.8); // Sets myval to -3.
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floor
( W; D. [5 W/ C. D, d9 ]$ M9 x) E(num num)

地板，向下取整。

Example

double myval = floor(2.3); // Sets myvalto 2.
0 w& q3 i+ C; v0 O4 Adouble myval = floor(3.8); // Sets myval to 3.
$ |7 R% \& N! Y1 J' Qdouble myval = floor(-2.3); // Sets myval to -3.
: ^- b# X1 ~+ fdouble myval = floor(-3.8); // Sets myval to -4.
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round
1 o  a1 E& U8 O(num value[, num precision])

根据指定的小数位数进行四舍五入。

Example

int mynum1 = round(3.6269);
% G+ }; h. W8 g# n! F2 \9 }int mynum2 = round(3.6269,2);

( E1 ]+ A% C! @mynum1 will be 4, and mynum2 will be 3.63.

trunc
(num value)

去除小数部分取整。Truncation

Example

trunc(2.478), returns 2
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6 i) ]* i2 y& Z+ N! F4 Ttrunc(2.95), returns 2
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frac
& S3 i& n8 |) m- `(num value)

取小数点之后的部分。

Example

frac(3.124) returns 0.124
$ K2 m2 k  e/ U- R0 J* b$ sfrac(-16.12) returns -0.12
: x+ R% H9 o6 \+ @$ f" }: E' I# ufrac(12) returns 0.0
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sign
, j  }  Z5 ?2 h4 J* W' B(num value)

决断正负零，正数返回1，负数返回-1，0返回0。

Example

sign(-1)

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fabs
(num value)

绝对值。

Example

if(fabs(x1 - x2) > 5)

factorial
(num value)

阶乘。

Example

factorial(5)

9 _% a4 w: @" X; lThis calculates the factorial of 5, which is 1*2*3*4*5 = 120
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fmod
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取余。

Description

Remainder of value1/value2. fmod returnsthe floating-point remainder of value1 / value2. If the value of b is 0.0, fmodreturns a quiet NaN.
This command is great for getting a repeating set ofnumbers because no matter what value1 is, so long as value2 is unchanged, fmodwill return a set of numbers that keeps repeating itself.

Example

fmod(10,3) This returns the remainder of 10/3, which is 1.0
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9 m6 [$ b- l+ ]* J" K1 v, e* Pif(fmod(current.stats.output,10) == 0)

If this condition was in the OnExit of an object in the model, it would be truewith every 10th flowitem that exits, starting with the 10th flowitem.
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pow
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乘方。

Example

double myval = pow(2,3); Sets myval to 8.
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sqr
3 h, v- g3 Q" q9 N(num value)

平方Square of value.

Example

sqr(2)

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sqrt
(num value)

平方根Square root of value

Example

sqrt(10) This expression will return 3.16

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比如，我们要计算托盘上有多少层货物。
默认情况下，pallet上面每层可以放置4个box。也就是说，1,2,3,4个box都算1层，5,6,7,8个box都算是2层。
. ?5 w. V/ b; ?  h1 Y9 y此时可以用ceil函数向上取整，ceil(content(pallet)/4)即可得到正确的层数。

受教了

Mark~谢谢加老师的分享

这个真的很有用~谢谢加老师、